Friday, May 25, 2007

Five children each grabbed a handful of chocolates from a jar. Arnold had seven more chocolates in his hand than Beatrice, and Beatrice had six chocolates less than Claudia. Edgar had three more than David and Claudia had one more than Edgar. Beatrice and Edgar had nine chocolates between them. How many chocolates did each child have total?

5 comments:

Jake said...

D'oh! Algebra!

30 chocolates were pilfered quite inequitably by those grubby little children. I hope they were Lindt!

pamigelsrud said...

So I was wondering if anyone else would figure this out before me. Guess I win, although this wasn't really a contest. But I like winning, so I'm fine with calling myself the winner. :-)

The answers are:
A=9, B=2, C=8, D=4, E=7

pamigelsrud said...

PS - nice try, Jake :-)

Jake said...

Which adds up to 30! :)

I didn't bother putting the breakdown, since I misread the question to be for the total... oh well...

pamigelsrud said...

oh... well, now i feel stupid!